document.write( "Question 555543: 5^(3y-1)=2^y\r
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Algebra.Com's Answer #362044 by lwsshak3(11628)\"\" \"About 
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5^(3y-1)=2^y
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\n" ); document.write( "5^(3y-1)=2^y
\n" ); document.write( "(3y-1)log(5)=ylog(2)
\n" ); document.write( "(3y-1)/y=log(2)/log(5)≈.4307
\n" ); document.write( "3y-1=.4307y
\n" ); document.write( "3y-.4307y=1
\n" ); document.write( "2.5693y=1
\n" ); document.write( "y≈.3892
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