document.write( "Question 556089: find three consecutive integers such that the product of the first and the second is equal to the product of -6 and the third. \n" ); document.write( "

Algebra.Com's Answer #362038 by TutorDelphia(193) $\"\"$ $\"About$

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Three consecutive integers. If we say the first one is n, than the 3 will be n, n+1 and n+2
\n" ); document.write( "Therefore we can write the problem as
\n" ); document.write( "n*(n+1)=-6*(n+2)
\n" ); document.write( "Distribute the n and -6
\n" ); document.write( " $\"n%5E2%2Bn=-6n-12\"$
\n" ); document.write( "Add 6n to both sides
\n" ); document.write( " $\"n%5E2%2B7n=-12\"$
\n" ); document.write( "add 12 to both sides
\n" ); document.write( " $\"n%5E2%2B7n%2B12=0\"$
\n" ); document.write( "factor
\n" ); document.write( "(n+3)(n+4)=0
\n" ); document.write( "n=-3 or -4\r
\n" ); document.write( "\n" ); document.write( "So our integers would be -3,-2,-1
\n" ); document.write( "or -4,-3,-2\r
\n" ); document.write( "\n" ); document.write( "-3*-2=-1*6
\n" ); document.write( "6=6\r
\n" ); document.write( "\n" ); document.write( "-4*-3=-2*-6
\n" ); document.write( "12=12\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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