document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=556071>Question 556071</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In one evening, a pizza parlor collected 700 coins, for a total of $145. If the coins are all dimes and quarters, how many of each kind are there? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #362030 by </B><A HREF=/tutors/aboutme.mpl?userid=TutorDelphia><B>TutorDelphia(193)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=TutorDelphia><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=TutorDelphia><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=362030\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Dimes and quarters add together to equal 700 coins:<BR>\n" );
document.write( "d+q=700<BR>\n" );
document.write( "Dimes are worth 10 cents each and quarters 25 and if we multiply how many we have times their value and add it together we'll get the amount of money we have<BR>\n" );
document.write( ".10d+.25q=145<BR>\n" );
document.write( "Solve the first equation for d<BR>\n" );
document.write( "d=700-q<BR>\n" );
document.write( "Sub 700-q in for d in the second equation:<BR>\n" );
document.write( ".10*(700-q)+.25q=145<BR>\n" );
document.write( "Distribute<BR>\n" );
document.write( "70-.10q+.25q=145<BR>\n" );
document.write( "combine like terms<BR>\n" );
document.write( "70+.15q=145<BR>\n" );
document.write( "subtract 70 from both sides<BR>\n" );
document.write( ".15q=75<BR>\n" );
document.write( "divide .15 from both sides<BR>\n" );
document.write( "q=500<BR>\n" );
document.write( "Plug in 500 for q<BR>\n" );
document.write( "d+500=700<BR>\n" );
document.write( "d=200 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );