document.write( "Question 556012: bill is 4 times as old as john.five year ago the sum of their ages was 50 how old are they now \n" ); document.write( "
Algebra.Com's Answer #362019 by TutorDelphia(193)![]() ![]() You can put this solution on YOUR website! bill is 4 times as old as john \n" ); document.write( "b=4j \n" ); document.write( "Five years ago bill was b-5 and john was j-5 (if bill is 48 now, he was 43, 5 years ago) \n" ); document.write( "(b-5)+(j-5)=50 \n" ); document.write( "combine like terms \n" ); document.write( "b+j-10=50 \n" ); document.write( "add 10 to both sides \n" ); document.write( "b+j=60 \n" ); document.write( "sub in 4j for b \n" ); document.write( "4j+j=60 \n" ); document.write( "combine like terms \n" ); document.write( "5j=60 \n" ); document.write( "divide by 5 \n" ); document.write( "j=12 \n" ); document.write( "plug in 12 for j \n" ); document.write( "b=48 \n" ); document.write( " |