document.write( "Question 555789: How many gallons of a 50% alcohol solution must be mixed with 80 gallons of a 14% solution to obtain a solution that is 40% alcohol? \n" ); document.write( "
Algebra.Com's Answer #361937 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! .5x+80*.14=.4*(80+x) \n" ); document.write( ".5x+80*.14=.4*80+.4x \n" ); document.write( ".1x=.4*80-80*.14 \n" ); document.write( ".1x=80*(.4-.14) \n" ); document.write( ".1x=80*(.26) \n" ); document.write( "multiply by 10 \n" ); document.write( "x=80*2.6 \n" ); document.write( "x=208 gallons\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |