document.write( "Question 555662: y=-x+10
\n" ); document.write( " y=x+2 \n" ); document.write( "

Algebra.Com's Answer #361891 by Maths68(1474) $\"\"$ $\"About$

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y=-x+10.........(1)
\n" ); document.write( "y=x+2...........(2)
\n" ); document.write( "Add (1) and (2)
\n" ); document.write( "y=-x+10
\n" ); document.write( "y=x+2
\n" ); document.write( "---------------------
\n" ); document.write( "2y=12
\n" ); document.write( "2y/2=12/2
\n" ); document.write( "y=6
\n" ); document.write( "Put the value of y in (2)
\n" ); document.write( "y=x+2...........(2)
\n" ); document.write( "6=x+2
\n" ); document.write( "6-2=x
\n" ); document.write( "4=x
\n" ); document.write( "x=4\r
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\n" ); document.write( "\n" ); document.write( "x,y=4,6\r
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\n" ); document.write( "\n" ); document.write( "Check
\n" ); document.write( "======
\n" ); document.write( "Put the values of x and y in (1)
\n" ); document.write( "y=-x+10.........(1)
\n" ); document.write( "6=-4+10
\n" ); document.write( "6=6
\n" ); document.write( "Put the values of x and y in (2)
\n" ); document.write( "y=x+2...........(2)
\n" ); document.write( "6=4+2
\n" ); document.write( "6=6
\n" ); document.write( " \n" ); document.write( "

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