document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=555607>Question 555607</A>: <I><SPAN STYLE=\"word-break: break-all;\"> bruce is 38 years old, his son is 8 years old. In how many years will bruce be 3 times older than his son? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #361888 by </B><A HREF=/tutors/aboutme.mpl?userid=Maths68><B>Maths68(1474)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Maths68><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Maths68><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=361888\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let after x years Bruce will be three times older then his son \r<BR>\n" );
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document.write( "After x years Bruce will be = 38+x<BR>\n" );
document.write( "After x years Son  will be = 8+x<BR>\n" );
document.write( "Then<BR>\n" );
document.write( "Bruce will be three times as old as his son<BR>\n" );
document.write( "38+x=3(8+x)<BR>\n" );
document.write( "38+x=24+3x<BR>\n" );
document.write( "x-3x=24-38<BR>\n" );
document.write( "-2x=-14<BR>\n" );
document.write( "-2x/-2=-14/-2<BR>\n" );
document.write( "x=7\r<BR>\n" );
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document.write( "After 7 years Bruce will be three times older then his son\r<BR>\n" );
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document.write( "After 7 years Bruce will be = 38+x = 38+7 = 45<BR>\n" );
document.write( "After 7 years Son  will be = 8+x = 8+7 = 15\r<BR>\n" );
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