document.write( "Question 555620: A hemispherical dome holds a volume of 486 pie ft^3. Find the surface area. (omit the area of the circle)
\n" ); document.write( "* please help me!!!*** \n" ); document.write( "
Algebra.Com's Answer #361868 by mathstutor494(120)\"\" \"About 
You can put this solution on YOUR website!
A hemispherical dome holds a volume of 486 pie ft^3. Find the surface area.\r
\n" ); document.write( "\n" ); document.write( "Volume of Semisphere = 2/3 pi r^3\r
\n" ); document.write( "\n" ); document.write( "> 486 = 2/3 pi r^3
\n" ); document.write( "> r^3 = (486*3)/(2*pi)\r
\n" ); document.write( "\n" ); document.write( "Hence r = 9/ 1.46 > 6.16
\n" ); document.write( "Surface Area of a Semisphere = 2 pi r^2
\n" ); document.write( "Area of a circle = pi r^2\r
\n" ); document.write( "\n" ); document.write( "So Surface Area of a Semisphere less Area of a circle
\n" ); document.write( "> 2 pi r^2 - pi r^2\r
\n" ); document.write( "\n" ); document.write( "> pi r^2\r
\n" ); document.write( "\n" ); document.write( "Substituting values of pi & r from above\r
\n" ); document.write( "\n" ); document.write( "> 3.14* (6.16)^2
\n" ); document.write( "> 119.15 ft^2\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );