document.write( "Question 555284: Hi i am wondering how to solve for the \"p\" value in parabolas. from what i understand you are supposed to do 1/4a but everytime i try this it is unsuccessful. if anyone could help it would be very appreciated. the problem i need the p value for is as follows. 1/4(x-3)^2-1 \n" ); document.write( "
Algebra.Com's Answer #361846 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Hi i am wondering how to solve for the \"p\" value in parabolas. from what i understand you are supposed to do 1/4a but everytime i try this it is unsuccessful. if anyone could help it would be very appreciated. the problem i need the p value for is as follows. 1/4(x-3)^2-1 \n" ); document.write( "** \n" ); document.write( "Rewrite the formula with the y in it. \n" ); document.write( "y=1/4(x-3)^2-1 \n" ); document.write( "y+1=1/4(x-3)^2 \n" ); document.write( "(x-3)^2=4(y+1) \n" ); document.write( "This is the standard form of equation for parabolas showing the focus and directrix: \n" ); document.write( "(x-h)^2=4p(y-k), with (h,k) being the (x,y) coordinates of the vertex. \n" ); document.write( "For given equation: \n" ); document.write( "vertex: (3,-1) \n" ); document.write( "axis of symmetry: x=3 (parabola opens upwards) \n" ); document.write( "4p=4 \n" ); document.write( "p=1 \n" ); document.write( " |