document.write( "Question 555284: Hi i am wondering how to solve for the \"p\" value in parabolas. from what i understand you are supposed to do 1/4a but everytime i try this it is unsuccessful. if anyone could help it would be very appreciated. the problem i need the p value for is as follows. 1/4(x-3)^2-1 \n" ); document.write( "
Algebra.Com's Answer #361846 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
Hi i am wondering how to solve for the \"p\" value in parabolas. from what i understand you are supposed to do 1/4a but everytime i try this it is unsuccessful. if anyone could help it would be very appreciated. the problem i need the p value for is as follows. 1/4(x-3)^2-1
\n" ); document.write( "**
\n" ); document.write( "Rewrite the formula with the y in it.
\n" ); document.write( "y=1/4(x-3)^2-1
\n" ); document.write( "y+1=1/4(x-3)^2
\n" ); document.write( "(x-3)^2=4(y+1)
\n" ); document.write( "This is the standard form of equation for parabolas showing the focus and directrix:
\n" ); document.write( "(x-h)^2=4p(y-k), with (h,k) being the (x,y) coordinates of the vertex.
\n" ); document.write( "For given equation:
\n" ); document.write( "vertex: (3,-1)
\n" ); document.write( "axis of symmetry: x=3 (parabola opens upwards)
\n" ); document.write( "4p=4
\n" ); document.write( "p=1
\n" ); document.write( "
\n" );