document.write( "Question 555505: 3y^2-x-6y+5=0 What kind of conic is this? And how to put in standard form? \n" ); document.write( "
Algebra.Com's Answer #361838 by lwsshak3(11628)\"\" \"About 
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3y^2-x-6y+5=0 What kind of conic is this? And how to put in standard form?
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\n" ); document.write( "3y^2-x-6y+5=0
\n" ); document.write( "x=3y^2-6y+5=0
\n" ); document.write( "complete the square:
\n" ); document.write( "x=3(y^2-2y+1)+5-3
\n" ); document.write( "x=3(y-1)^2+2
\n" ); document.write( "This is an equation of a parabola which opens rightwards with vertex at (2,1)
\n" ); document.write( "Standard form: x=A(y-k)^2+h, with (h,k) being the (x,y) coordinates of the vertex. A is a multiplier which affects the narrowness of the curve.
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