document.write( "Question 555513: How to find a Parabola (these are some i cannot get right):
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document.write( "1. y=x^2-8x+13
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document.write( " 2.y+2x^2+32=-16x-1
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document.write( "and 3. 2x-y^2=4y+10 \n" );
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Algebra.Com's Answer #361836 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! How to find a Parabola (these are some i cannot get right): \n" ); document.write( ".. \n" ); document.write( "1. y=x^2-8x+13 \n" ); document.write( "complete the square: \n" ); document.write( "y=(x^2-8x+16)+13-16 \n" ); document.write( "y=(x-4)^-3 \n" ); document.write( "This is an equation of a parabola which opens upwards and has a vertex at (4,-3) \n" ); document.write( "Standard form of equation: y=A(x-h)^2+k, (h,k) being the (x,y) coordinates of the vertex. \n" ); document.write( "A is a multiplier which affects the slope or steepness of the curve. \n" ); document.write( ".. \n" ); document.write( "2.y+2x^2+32=-16x-1 \n" ); document.write( "y=-2x^2-16x-33 \n" ); document.write( "complete the square: \n" ); document.write( "y=-2(x^2+8x+16)-33+32 \n" ); document.write( "y=-2(x+4)^2-1 \n" ); document.write( "This is an equation of a parabola which opens downwards and has a vertex at (-4,1) \n" ); document.write( "Standard form of equation: y=-A(x-h)^2+k, (h,k) being the (x,y) coordinates of the vertex. \n" ); document.write( ".. \n" ); document.write( "3. 2x-y^2=4y+10 \n" ); document.write( "2x=y^2+4y+10 \n" ); document.write( "divide by 2 \n" ); document.write( "x=(1/2)y^2+2y+5 \n" ); document.write( "complete the square: \n" ); document.write( "x=(1/2)(y^2+4y+4)+5-2 \n" ); document.write( "x=(1/2)(y+2)^2+3 \n" ); document.write( "This is an equation of a parabola which opens rightwards and has a vertex at (3,-2) \n" ); document.write( "Standard form of equation: x=A(y-k)^2+h, (h,k) being the (x,y) coordinates of the vertex. \n" ); document.write( " |