document.write( "Question 53921: Joe lived 1/6 of life as a child and 1/12 as a youth and 1/7 before he married and 5 years before son was born. Son live 1/2 of his life then Joe lived 4 more years. How old was Joe when he died. \n" ); document.write( "

Algebra.Com's Answer #36180 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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Joe lived 1/6 of life as a child and 1/12 as a youth and 1/7 before he married and 5 years before son was born. Son live 1/2 of his life then Joe lived 4 more years. How old was Joe when he died.
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\n" ); document.write( "Just add up fractions & years given, it should add up to the total years of his life
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\n" ); document.write( "Let x = Joe's life-time
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\n" ); document.write( "x = (1/6)x + (1/12)x + (1/7)x + 5 + (1/2x) + 4
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\n" ); document.write( "A good common denominator would be 84
\n" ); document.write( "x = (14/84)x + (7/84)x + (12/84)x + 5 + (42/84) + 4
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\n" ); document.write( "mult equation by 84:
\n" ); document.write( "84x = 14x + 7x + 12x + 420 + 42x + 336
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\n" ); document.write( "84x = 75x + 756
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\n" ); document.write( "You should be able to solve it now
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