Algebra.Com's Answer #3618 by khwang(438)![\"\"](\"/images/stars/stars-10.gif\")   You can put this solution on YOUR website! Note f(0) =0,the graph passing the origin.\r \n" ); document.write( "\n" ); document.write( " The vertical asymptote is x+1 =0. We see that \n" ); document.write( " when x-->-1+(right), f(x)-->-oo; when x-->-1-(left), f(x)-->oo;\r \n" ); document.write( "\n" ); document.write( " When x-->oo(or -oo) , y =f(x)--> 1. the horizontal asymptote is y=1.\r \n" ); document.write( "\n" ); document.write( " Since f(x) = 1- 1/(x+1) \n" ); document.write( " f'(x) = 1/(x+1)^2, so f'(x) > 0 for all x (not -1) \n" ); document.write( " and f is an increasing on (1,+oo) or (-oo, 1) \n" ); document.write( " \n" ); document.write( " Also ,plot points (1,f(1)), (-2,f(-2)), etc\r \n" ); document.write( "\n" ); document.write( " Then you will see the graph.\r \n" ); document.write( "\n" ); document.write( " Another way:by f(x) = 1- 1/(x+1). \n" ); document.write( " It means f is the composite of the reflection -1/(x+1) and the translation. \n" ); document.write( " x--> 1/(x+1) (a hyperbola) --> - 1/(x+1) --> 1- 1/(x+1) \n" ); document.write( " \n" ); document.write( " Kenny \n" ); document.write( " |