document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=555475>Question 555475</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 4x+3y=33<BR>\n" );
document.write( "6x+y=25 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #361790 by </B><A HREF=/tutors/aboutme.mpl?userid=kkasko><B>kkasko(46)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=kkasko><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=361790\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 4x+3y=33<BR>\n" );
document.write( "6x+y=25\r<BR>\n" );
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document.write( "4x+3y=33<BR>\n" );
document.write( "-4x.      -4x<BR>\n" );
document.write( "3y=-4x+33<BR>\n" );
document.write( "/3.    /3. /3<BR>\n" );
document.write( "Y=-4/3x+11\r<BR>\n" );
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document.write( "6x+y=25<BR>\n" );
document.write( "-6x.    -6x<BR>\n" );
document.write( "y=-6x+25\r<BR>\n" );
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document.write( "You can now create a graph by the starting y intercepts and the slope of each line. For instance the first equation starts at (0,11) and goes down 4 right 3. Then once you have gone to the edge of the graphing paper. Start again at (0,11) and go down 4 left 3. \r<BR>\n" );
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document.write( "The second equation starts at (0,25) and has a slope of -6/1 which means it goes down 6 and right one. Then after goes as far right as possible. The two lines should connect at (3,7). This is the solution to the problem. \r<BR>\n" );
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document.write( " </SPAN>\n" );
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