document.write( "Question 555447: My question is on linear systems : Angie is twice as old as Amelie. One year ago the sum of their ages was 10. How old is each now? I tried a couple different systems like 2y=x and x+y = 10 but I kept trying to work it out with others to but I can't get it. Please help me! Thank you! \n" ); document.write( "
Algebra.Com's Answer #361782 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Angie is twice as old as Amelie. One year ago the sum of their ages was 10.
\n" ); document.write( " How old is each now?
\n" ); document.write( ":
\n" ); document.write( "Assume you had:
\n" ); document.write( "x = Angie
\n" ); document.write( "y = Amelie
\n" ); document.write( ":
\n" ); document.write( "\"Angie is twice as old as Amelie.\"
\n" ); document.write( "x = 2y
\n" ); document.write( ":
\n" ); document.write( "\"One year ago the sum of their ages was 10.\"
\n" ); document.write( "(x-1) + (y-1) = 10
\n" ); document.write( "x + y - 2 = 10
\n" ); document.write( "x + y = 10 + 2
\n" ); document.write( "x + y = 12
\n" ); document.write( "from the 1st equation, replace x with 2y
\n" ); document.write( "2y + y = 12
\n" ); document.write( "3y = 12
\n" ); document.write( "y = 12/3
\n" ); document.write( "y = 4 yrs is Amelie's present age, then obviously
\n" ); document.write( "x = 2(4) = 8 yrs is Angies age
\n" ); document.write( ";
\n" ); document.write( ":
\n" ); document.write( "See if this checks out in the statement:
\n" ); document.write( "\" One year ago the sum of their ages was 10. \"
\n" ); document.write( "8-1 + 4-1 = 10\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " How old is each now? 8 and 4 \n" ); document.write( "
\n" );