document.write( "Question 555297: It is estimated that t years from now the population of a particular city will be....\r
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document.write( "P = t^2 - 24t + 96,000\r
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document.write( "How many years from now will the population be 95,865?\r
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document.write( "Thanks in advance, I appreciate it! \n" );
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Algebra.Com's Answer #361729 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! P = t^2 - 24t + 96000 \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "95865 = t^2 - 24t + 96000 \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "0 = t^2 - 24t + 96000 - 95865 \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "0 = t^2 - 24t + 135\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now use the quadratic formula to solve for t:\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "t = (-b+-sqrt(b^2-4ac))/(2a)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "t = (-(-24)+-sqrt((-24)^2-4(1)(135)))/(2(1))\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "t = (24+-sqrt(576-(540)))/(2)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "t = (24+-sqrt(36))/2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "t = (24+sqrt(36))/2 or t = (24-sqrt(36))/2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "t = (24+6)/2 or t = (24-6)/2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "t = 30/2 or t = 18/2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "t = 15 or t = 9\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So this means that in 15 or 9 years the population will be 95,865\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Note: the population will reach 95,865 in 9 years first, dip below 95865 and then climb back up to 95,865 when t = 15\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If you need more help, email me at jim_thompson5910@hotmail.com\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Jim\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |