document.write( "Question 53903This question is from textbook algebra and trigonometry
\n" ); document.write( ": how do i find the altitude for this problem?,\r
\n" ); document.write( "\n" ); document.write( "a jetliner covered a horizontal distance of 5 mi. while following a flight path with slope 0.25.how much altitude did it gain? \n" ); document.write( "
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a jetliner covered a horizontal distance of 5 mi. while following a flight path with slope 0.25.how much altitude did it gain?
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\n" ); document.write( "There is a very simple way to do this: One definition of slope is \"rise over run\". Convert the slope of .25 to the fraction 1/4. That means for every 4 ft horizontally, it rises 1 ft vertically.
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\n" ); document.write( "Find the rise (altitude) for a horizontal value of 5 miles.
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\n" ); document.write( " \"1%2F4\" = \"A%2F5\"
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\n" ); document.write( "Cross mult and you have:
\n" ); document.write( " 4A = 1*5
\n" ); document.write( " A = 5/4
\n" ); document.write( " A = 1.25 miles high or 5280*1.25 = 6600 ft is the altitude
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\n" ); document.write( "However, I see you are studying Linear equations so they probably want the equation for this: y being the vertical, would be the altitude, the plane will be starting at the origin. (0,0) so the y intercept will be 0
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\n" ); document.write( "Using the slope/intercept formula: m = .25, b=0, x = 5
\n" ); document.write( "y = mx + b
\n" ); document.write( "y = .25x + 0
\n" ); document.write( "y = .25(5)
\n" ); document.write( "y = 1.25 miles
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\n" ); document.write( "you can picture it as a right triangle; the sides are 5 and 1.25 and the hypotenuse is the path of the plane.
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