document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=555266>Question 555266</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help solv.  A digital photgraph is 30 pixel longer than it is wide and has a total area of 4000 pixels. Find the dimensions of this photograph. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #361709 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=361709\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x(x+30)=4000\r<BR>\n" );
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document.write( "x^2+30x=4000\r<BR>\n" );
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document.write( "x^2+30x-4000=0\r<BR>\n" );
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document.write( "Now use the quadratic formula to solve:\r<BR>\n" );
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document.write( "x = (-b+-sqrt(b^2-4ac))/(2a)\r<BR>\n" );
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document.write( "x = (-(30)+-sqrt((30)^2-4(1)(-4000)))/(2(1))\r<BR>\n" );
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document.write( "x = (-30+-sqrt(900-(-16000)))/(2)\r<BR>\n" );
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document.write( "x = (-30+-sqrt(16900))/2\r<BR>\n" );
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document.write( "x = (-30+sqrt(16900))/2 or x = (-30-sqrt(16900))/2\r<BR>\n" );
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document.write( "x = (-30+130)/2 or x = (-30-130)/2\r<BR>\n" );
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document.write( "x = 100/2 or x = -160/2\r<BR>\n" );
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document.write( "x = 50 or x = -80\r<BR>\n" );
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document.write( "Ignore the negative solution. So the dimensions are 50 by 80 pixels.\r<BR>\n" );
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document.write( "Jim</font></b><BR>\n" );
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