document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=555155>Question 555155</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me with this linear inequality  2k-3/4 < 3<BR>\n" );
document.write( "I have tried to multiply both sides by 12 as a lowest common denominator and I am not getting the answer right.  I need help how how to solve it.  I cannot locate a problem like this one in my textbook.\r<BR>\n" );
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document.write( "Thank you! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #361664 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=361664\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2k - 3/4 < 3<BR>\n" );
document.write( "multiply both sides by 4, to get rid of the denominator<BR>\n" );
document.write( "4(2k) - 3 < 4(3)<BR>\n" );
document.write( "8k - 3 < 12<BR>\n" );
document.write( "8k < 12 + 3<BR>\n" );
document.write( "8k < 15<BR>\n" );
document.write( "k < <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=15%2F8 ALIGN=MIDDLE  ALT=\"15%2F8\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "or<BR>\n" );
document.write( "k < 1.875<BR>\n" );
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