document.write( "Question 555083: Solve the following system of equations.\r
\n" ); document.write( "\n" ); document.write( "2x + y = 3
\n" ); document.write( "x = 2y - 1\r
\n" ); document.write( "\n" ); document.write( "Make sure there are NO SPACES in your answer. Include a comma in your answer.
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Algebra.Com's Answer #361628 by kkasko(46)\"\" \"About 
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Solve the following system of equations.\r
\n" ); document.write( "\n" ); document.write( "2x + y = 3
\n" ); document.write( "x = 2y - 1\r
\n" ); document.write( "\n" ); document.write( "Make sure there are NO SPACES in your answer. Include a comma in your answer.
\n" ); document.write( "It looks like I could substitute the x=2y-1. Into 2x+y=3
\n" ); document.write( "2(2y-1)+y=3
\n" ); document.write( "4y-2+y=3
\n" ); document.write( "5y=5
\n" ); document.write( "y=1
\n" ); document.write( "x=2(1)-1
\n" ); document.write( "x=1
\n" ); document.write( "(1,1)
\n" ); document.write( "CHECK
\n" ); document.write( "2x+y=3
\n" ); document.write( "2(1)+(1)=3
\n" ); document.write( "2+1=3
\n" ); document.write( "3=3
\n" ); document.write( "Left hand side=Right hand side
\n" ); document.write( "Check other equation
\n" ); document.write( "x=2y-1
\n" ); document.write( "1=2(1)-1
\n" ); document.write( "1=1
\n" ); document.write( "Therefore the solution is (1,1). Since the left hand side= right hand side in each equation
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