document.write( "Question 554767: Hello, my algebra word problem is this \"Use two variables and two equations to solve the problem. Part of $9000 was invested at 10% interest and the rest at 12%. If the annual income from these investments was $1020 how much was invested at rate? \n" ); document.write( "
Algebra.Com's Answer #361617 by ankor@dixie-net.com(22740)\"\" \"About 
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Use two variables and two equations to solve the problem.
\n" ); document.write( " Part of $9000 was invested at 10% interest and the rest at 12%.
\n" ); document.write( "If the annual income from these investments was $1020 how much was invested at rate?
\n" ); document.write( ":
\n" ); document.write( "Let x = amt invested at 10%
\n" ); document.write( "Let y = amt invested at 12%
\n" ); document.write( ":
\n" ); document.write( "The amt equation
\n" ); document.write( "x + y = 9000
\n" ); document.write( "Rearrange for substitution
\n" ); document.write( "x = (9000-y)
\n" ); document.write( ":
\n" ); document.write( "the interest equation
\n" ); document.write( ".10x + .12y = 1020
\n" ); document.write( "substitute (9000-y) for x, solve for y
\n" ); document.write( ".10(9000-y) + .12y = 1020
\n" ); document.write( "900 - .10y + .12y = 1020
\n" ); document.write( ".02y = 1020 - 900
\n" ); document.write( ".02y = 120
\n" ); document.write( "y = \"120%2F.02\"
\n" ); document.write( "y = $6000 invested at 12%
\n" ); document.write( ":
\n" ); document.write( "You should be able to find x, check your solutions in both equations
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