document.write( "Question 554767: Hello, my algebra word problem is this \"Use two variables and two equations to solve the problem. Part of $9000 was invested at 10% interest and the rest at 12%. If the annual income from these investments was $1020 how much was invested at rate? \n" ); document.write( "
Algebra.Com's Answer #361617 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Use two variables and two equations to solve the problem. \n" ); document.write( " Part of $9000 was invested at 10% interest and the rest at 12%. \n" ); document.write( "If the annual income from these investments was $1020 how much was invested at rate? \n" ); document.write( ": \n" ); document.write( "Let x = amt invested at 10% \n" ); document.write( "Let y = amt invested at 12% \n" ); document.write( ": \n" ); document.write( "The amt equation \n" ); document.write( "x + y = 9000 \n" ); document.write( "Rearrange for substitution \n" ); document.write( "x = (9000-y) \n" ); document.write( ": \n" ); document.write( "the interest equation \n" ); document.write( ".10x + .12y = 1020 \n" ); document.write( "substitute (9000-y) for x, solve for y \n" ); document.write( ".10(9000-y) + .12y = 1020 \n" ); document.write( "900 - .10y + .12y = 1020 \n" ); document.write( ".02y = 1020 - 900 \n" ); document.write( ".02y = 120 \n" ); document.write( "y = \n" ); document.write( "y = $6000 invested at 12% \n" ); document.write( ": \n" ); document.write( "You should be able to find x, check your solutions in both equations \n" ); document.write( " |