document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=53907>Question 53907</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Help I am in college and studying for a test.  I don't understand how to do this question??????????/\r<BR>\n" );
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document.write( "you have two different triangles.<BR>\n" );
document.write( "the hypotenuse of the first is 6 inches and the second if 14 inches.<BR>\n" );
document.write( "which would have the greater area and why? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #36161 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=36161\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Help I am in college and studying for a test. I don't understand how to do this question??????????/  \r<BR>\n" );
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document.write( "you have two different triangles.<BR>\n" );
document.write( "the hypotenuse of the first is 6 inches and the second if 14 inches.<BR>\n" );
document.write( "which would have the greater area and why?\r<BR>\n" );
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document.write( "the 2 triangles given are right angled as it mentions the word hypotenuse,which means the side opposite 90 degree angle.hence we have one side = hypotenuse =6\" or 14\" and an angle=90 deg.but we need 3 dimensions to fix a triangle.hence the given data does not firm up a triangle.<BR>\n" );
document.write( "area of right triangle = 0.5*a*b....where a and b are 2 legs or sides which are perpendicular to each other.<BR>\n" );
document.write( "from pythogarus theorem,we have <BR>\n" );
document.write( "a^2+b^2=6^2=36...in one triangle and <BR>\n" );
document.write( "p^2+q^2=14^2=196..in the second triangle..<BR>\n" );
document.write( "but this in no way fixes a&b for first triangle or p&q for the second triangle.<BR>\n" );
document.write( "CASE 1<BR>\n" );
document.write( "for example in triangle 1....<BR>\n" );
document.write( "a=b could be sqrt(18) each giving an area of 0.5*sqrt(18)*sqrt(18)=9 sq.inches<BR>\n" );
document.write( "on the other hand in the second triangle...<BR>\n" );
document.write( "p could be 0.1...q = sqrt(195.99)...giving an area of 0.5*0.1*sqrt(195.99)=0.7 about.....which is much less than the area of first triangle...<BR>\n" );
document.write( "CASE 2<BR>\n" );
document.write( "on the other hand it could be otherway round ....<BR>\n" );
document.write( "a=0.1....b=sqrt(35.99)......area=0.5*0.1*sqrt(35.99)=0.3 about<BR>\n" );
document.write( "where as <BR>\n" );
document.write( "p=sqrt(98)=q.....with an area = 0.5*sqrt(98)sqrt(98)=49 sq.inches<BR>\n" );
document.write( "which gives higher area for second triangle..<BR>\n" );
document.write( "SO THE ANSWER IS ... EITHER TRIANGLE COULD BE  BIGGER in AREA DEPENDING ON THE <BR>\n" );
document.write( "3 RD.DIMENSION WHICH IS NOT GIVEN.THE GIVEN DATA IS INSUFFICIENT TO CONCLUDE THAT ONE TRIANGLE IS BIGGER IN AREA THAN THE OTHER. </SPAN>\n" );
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