document.write( "Question 555001: A plane makes the trip from Acton to Banville at 800 km/h. The return, at 1000 km/h, takes 1/2 hour less than the initial flight. Find the distance between the towns. \n" ); document.write( "
Algebra.Com's Answer #361603 by josmiceli(19441)\"\" \"About 
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Let \"t\" = time in hours for 1st flight
\n" ); document.write( "Let \"d\" = distance between towns in km
\n" ); document.write( "Equation for A to B:
\n" ); document.write( "\"+d+=+800t+\"
\n" ); document.write( "Equation for B to A:
\n" ); document.write( "\"+d+=+1000%2A%28+t+-+1.5+%29+\"
\n" ); document.write( "----------------------------
\n" ); document.write( "Bt substitution:
\n" ); document.write( "\"+800t+=+1000t+-+1500+\"
\n" ); document.write( "\"+200t+=+1500+\"
\n" ); document.write( "\"+t+=+7.5+\" hrs
\n" ); document.write( "and, since
\n" ); document.write( "\"+d+=+800t+\"
\n" ); document.write( "\"+d+=+800%2A7.5+\"
\n" ); document.write( "\"+d+=+6000+\"
\n" ); document.write( "The distance between the towns is 6,000 km
\n" ); document.write( "check:
\n" ); document.write( "\"+d+=+1000%2A%28+t+-+1.5+%29+\"
\n" ); document.write( "\"+d+=+1000%2A%28+7.5+-+1.5+%29+\"
\n" ); document.write( "\"+d+=+1000%2A6+\"
\n" ); document.write( "\"+d+=+6000+\"
\n" ); document.write( "OK\r
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