document.write( "Question 555010: What quantity of pure acid must be added to 500 mL of a 25% acid solution to produce a 75% acid solution? \n" ); document.write( "

Algebra.Com's Answer #361600 by josmiceli(19441) $\"\"$ $\"About$

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let $\"+x+\"$ = ml of pure acid needed
\n" ); document.write( " $\"+.25%2A500+=+125+\"$ ml of pure acid in 25% solution
\n" ); document.write( "------------------
\n" ); document.write( " $\"+%28+x+%2B+125+%29+%2F+%28+x+%2B+500+%29+=+.75+\"$
\n" ); document.write( " $\"+x+%2B+125+=+.75%2A%28+x+%2B+500+%29+\"$
\n" ); document.write( " $\"+x+%2B+125+=+.75x+%2B+375+\"$
\n" ); document.write( " $\"+.25x+=+375+-+125+\"$
\n" ); document.write( " $\"+.25x+=+250+\"$
\n" ); document.write( " $\"+x+=+1000+\"$
\n" ); document.write( "1,000 ml of pure acid must be added
\n" ); document.write( "check answer:
\n" ); document.write( " $\"+%28+1000+%2B+125+%29+%2F+%28+1000+%2B+500+%29+=+.75+\"$
\n" ); document.write( " $\"+1125+%2F+1500+=+.75+\"$
\n" ); document.write( " $\"+1125+=+.75%2A1500+\"$
\n" ); document.write( " $\"+1125+=+1125+\"$
\n" ); document.write( "OK
\n" ); document.write( " \n" ); document.write( "

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