document.write( "Question 53918: When graphed using polar coordinates, the center of a regular nonagon is at the origin and one vertex is at (6,0 degrees) or (6,0 radians). Find the polar coordiantes of the other vertices in both degrees and radians. \n" ); document.write( "
Algebra.Com's Answer #36159 by AnlytcPhil(1806)\"\" \"About 
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When graphed using polar coordinates, the center of a regular nonagon is at the\r\n" );
document.write( "origin and one vertex is at (6,0 degrees) or (6,0 radians). Find the polar\r\n" );
document.write( "coordiantes of the other vertices in both degrees and radians\r\n" );
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document.write( "The vertices of a nonagon are the enpoints of the \"spokes\" of a \"9-spoke wheel\",\r\n" );
document.write( "each spoke measuring 6 units. \r\n" );
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document.write( "We divide 360° into 9 parts, 360°/9 = 40°.  So the \"spokes\" are 40° apart, so\r\n" );
document.write( "the vertices have as their second coordinates\r\n" );
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document.write( "0°, 40°, 80°, 120°, 160°, 200°, 240°, 280°, 320°\r\n" );
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document.write( "Each \"spoke\" is 6 units long, so the polar coordinates for the 9 vertices are\r\n" );
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document.write( "(6,0°), (6,40°), (6,80°), (6,120°), (6,160°), (6,200°), (6,240°), (6,280°), (6,320°)\r\n" );
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document.write( "In radians, 40° = 40(p/180) = 2p/9\r\n" );
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document.write( "So the polar coordinates in radians are:\r\n" );
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document.write( "(6,0), (6,2p/9), (6,4p/9), (6,6p/9), (6,8p/9), (6,10p/9), (6,12p/9), (6,14p/9), (6,16p/9)\r\n" );
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document.write( "Some of those fractions will reduce, so, after reducing those that will reduce\r\n" );
document.write( "the vertices of the nonagon in radians are:\r\n" );
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document.write( "(6,0), (6,2p/9), (6,4p/9), (6,2p/3), (6,8p/9), (6,10p/9), (6,4p/3), (6,14p/9), (6,16p/9)\r\n" );
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document.write( "Edwin
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