document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=554914>Question 554914</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the area of a square is 81 square centimeters, find the length of the diagonal. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #361578 by </B><A HREF=/tutors/aboutme.mpl?userid=MathTherapy><B>MathTherapy(10552)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=MathTherapy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=MathTherapy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=361578\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> \r<BR>\n" );
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document.write( "the area of a square is 81 square centimeters, find the length of the diagonal.\r<BR>\n" );
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document.write( "The diagonal of the square will form two 45-45 right triangles\r<BR>\n" );
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document.write( "In any 45-45 right triangle (isosceles right triangle), the hypotenuse equals one side, times square root of 2 (radical 2). Since one side = 9, then the length of the hypotenuse or the length of the diagonal can be written as:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight_green%289sqrt%282%29%29 ALIGN=MIDDLE  ALT=\"highlight_green%289sqrt%282%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > \r<BR>\n" );
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