document.write( "Question 554928: determine whether quadrilateral MATH is a parallelogram, a rectangle, a rhombus, or a square given the vertices M (5,4), A (3, -6), T ( 0, -10), and H (2,0). Note: I keep coming up with an answer that doesn't make sense, the other problems, no problem. \n" ); document.write( "
Algebra.Com's Answer #361576 by KMST(5328)![]() ![]() You can put this solution on YOUR website! We can calculate slopes of MA, AT, TH, HM, MT, and AH \n" ); document.write( "For MA, slope = \n" ); document.write( "For AT, slope = \n" ); document.write( "For TH, slope = \n" ); document.write( "For HM, slope = \n" ); document.write( "The fact that opposite sides of quadrilateral MATH have the same slope, means those pairs of opposite sides are parallel. That proves that it is a parallelogram. \n" ); document.write( "If the adjacent sides were perpendicular, we would have four right angles, and it would be a rectangle (or maybe even that special kind of rectangle that we call square). If the sides were perpendicular, the product of their slopes would be -1. \n" ); document.write( "However, \n" ); document.write( "Could it be a rhombus? If it were a rhombus, the diagonals would be perpendicular. \n" ); document.write( "Let's calculate the slope of the diagonals \n" ); document.write( "For MT, slope = \n" ); document.write( "For AH, slope = \n" ); document.write( "The product of the slopes, \n" ); document.write( "Quadrilateral MATH is a parallelogram. It is neither a square, nor a rectangle, nor a rhombus. \n" ); document.write( " |