document.write( "Question 554879: i need to find the nth term of a pattern with consecutive even numbers, ive tried many solutions but neither see to be working. please help. \n" ); document.write( "

Algebra.Com's Answer #361559 by KMST(5328) $\"\"$ $\"About$

You can put this solution on YOUR website!
If you have consecutive even numbers, each one is equal to the previous one plus 2.
\n" ); document.write( "That could be written as $\"a%5Bn%5D=a%5Bn-1%5D+%2B2\"$ or $\"a%5Bn%2B1%5D=a%5Bn%5D+%2B2\"$ .
\n" ); document.write( "If your first term is $\"a%5B1%5D\"$ , the second would be $\"a%5B2%5D=a%5B1%5D%2B2\"$ .
\n" ); document.write( "The third one would be $\"a%5B3%5D=a%5B2%5D%2B2%2Ba%5B2%5D=a%5B1%5D%2B2%2B2\"$
\n" ); document.write( "The fourth one would be $\"a%5B4%5D=a%5B1%5D%2B2%2B2%2B2\"$
\n" ); document.write( "The fifth one would be $\"a%5B5%5D=a%5B1%5D%2B2%2B2%2B2%2B2\"$ , and so on.
\n" ); document.write( "Each time you calculate the next term, you are adding 2.
\n" ); document.write( "When you get to the nth term, you have added n-1 times the number 2, so
\n" ); document.write( " $\"a%5Bn%5D=a%5B1%5D%2B2%28n-1%29\"$ \n" ); document.write( "

\n" );