document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=554914>Question 554914</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the area of a square is 81 square centimeters, find the length of the diagonal. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #361551 by </B><A HREF=/tutors/aboutme.mpl?userid=nyc_function><B>nyc_function(2741)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nyc_function><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nyc_function><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=361551\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The area of a square = side times side.\r<BR>\n" );
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document.write( "In short, A = s times s or s^2\r<BR>\n" );
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document.write( "81 = s^2\r<BR>\n" );
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document.write( "Taking the square root of both sides, we get s = 9cm.\r<BR>\n" );
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document.write( "To find the diagonal, we use the Pathygorean Theorem.\r<BR>\n" );
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document.write( "Let d = the diagonal representing the hypotenuse of the right triangle formed by two sides of the square and the diagonal.\r<BR>\n" );
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document.write( "(side)^2 + (side)^2 = (diagonal)^2\r<BR>\n" );
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document.write( "9^2 + 9^2 = d^2\r<BR>\n" );
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document.write( "81 + 81 = d^2\r<BR>\n" );
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document.write( "162 = d^2\r<BR>\n" );
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document.write( "Taking the square root of both sides, we get d =  sqrt{162}.\r<BR>\n" );
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document.write( "The length of the diagonal is the square root of 162 <BR>\n" );
document.write( "written as sqrt{162}.\r<BR>\n" );
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