document.write( "Question 554853: Solve the system by graphing: 3x + y = 5
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Algebra.Com's Answer #361501 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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Solved by pluggable solver: Solve the System of Equations by Graphing

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\n" ); document.write( " Start with the given system of equations:
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\n" ); document.write( " \"3x%2By=5\"
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\n" ); document.write( " \"-x%2B2y=-4\"
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\n" ); document.write( " In order to graph these equations, we need to solve for y for each equation.
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\n" ); document.write( " So let's solve for y on the first equation
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\n" ); document.write( " \"3x%2By=5\" Start with the given equation
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\n" ); document.write( " \"1y=5-3x\" Subtract \"3+x\" from both sides
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\n" ); document.write( " \"1y=-3x%2B5\" Rearrange the equation
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\n" ); document.write( " \"y=%28-3x%2B5%29%2F%281%29\" Divide both sides by \"1\"
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\n" ); document.write( " \"y=%28-3%2F1%29x%2B%285%29%2F%281%29\" Break up the fraction
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\n" ); document.write( " \"y=-3x%2B5\" Reduce
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\n" ); document.write( " Now lets graph \"y=-3x%2B5\" (note: if you need help with graphing, check out this solver)
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\n" ); document.write( " \"+graph%28+600%2C+600%2C+-10%2C+10%2C+-10%2C+10%2C+-3x%2B5%29+\" Graph of \"y=-3x%2B5\"
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\n" ); document.write( " So let's solve for y on the second equation
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\n" ); document.write( " \"-x%2B2y=-4\" Start with the given equation
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\n" ); document.write( " \"2y=-4%2Bx\" Add \"+x\" to both sides
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\n" ); document.write( " \"2y=%2Bx-4\" Rearrange the equation
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\n" ); document.write( " \"y=%28%2Bx-4%29%2F%282%29\" Divide both sides by \"2\"
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\n" ); document.write( " \"y=%28%2B1%2F2%29x%2B%28-4%29%2F%282%29\" Break up the fraction
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\n" ); document.write( " \"y=%281%2F2%29x-2\" Reduce
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\n" ); document.write( " Now lets add the graph of \"y=%281%2F2%29x-2\" to our first plot to get:
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\n" ); document.write( " \"+graph%28+600%2C+600%2C+-10%2C+10%2C+-10%2C+10%2C+-3x%2B5%2C%281%2F2%29x-2%29+\" Graph of \"y=-3x%2B5\"(red) and \"y=%281%2F2%29x-2\"(green)
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\n" ); document.write( " From the graph, we can see that the two lines intersect at the point (\"2\",\"-1\") (note: you might have to adjust the window to see the intersection)
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