document.write( "Question 554724: What is the awnser to this question?: l=12inches, w=4inches? Lenght and with. I have to find the perimeter and the area of the rectangle or square with the given demensions. Explain how u got it please. \n" ); document.write( "
Algebra.Com's Answer #361466 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Area:\r
\n" ); document.write( "\n" ); document.write( "A = LW\r
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\n" ); document.write( "\n" ); document.write( "A = 12*4\r
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\n" ); document.write( "\n" ); document.write( "A = 48\r
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\n" ); document.write( "\n" ); document.write( "Area is 48 square inches.\r
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\n" ); document.write( "\n" ); document.write( "-------------------------------------------------------\r
\n" ); document.write( "\n" ); document.write( "Perimeter\r
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\n" ); document.write( "\n" ); document.write( "P = 2L + 2W\r
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\n" ); document.write( "\n" ); document.write( "P = 2(12)+2(4)\r
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\n" ); document.write( "\n" ); document.write( "P = 24+8\r
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\n" ); document.write( "\n" ); document.write( "P = 32\r
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\n" ); document.write( "\n" ); document.write( "Perimeter is 32 inches.\r
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\n" ); document.write( "\n" ); document.write( "If you need more help, email me at jim_thompson5910@hotmail.com\r
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\n" ); document.write( "\n" ); document.write( "Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you\r
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