document.write( "Question 52659: Angela needs 20 quarts of 50% antifreeze solution in her radiator. She plans to obtain this by mixing some pure antifreeze with an appropriate amount of a 40% antifreeze solution. How many quarts of each solution should she use?
\n" ); document.write( "100% antifreeze? qts + 40% solution ? qts = 50% solution qts\r
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Algebra.Com's Answer #36137 by stanbon(75887)\"\" \"About 
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Angela needs 20 quarts of 50% antifreeze solution in her radiator. She plans to obtain this by mixing some pure antifreeze with an appropriate amount of a 40% antifreeze solution. How many quarts of each solution should she use?
\n" ); document.write( "100% antifreeze? qts + 40% solution ? qts = 50% solution qts
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\n" ); document.write( "Let amount of 40% solution be \"x\"; active ingrediant is 0.40x qts.
\n" ); document.write( "Amount of 100% solution is \"20-x\" qts; active ingrediant is (20-x) qts
\n" ); document.write( "Amount of mixed solution is 20 qts ; active ingrediant 0.50*20=10 qts.
\n" ); document.write( "EQUATION:
\n" ); document.write( "active + active = active
\n" ); document.write( "0.4x + 20-x = 10
\n" ); document.write( "-0.6x=-10
\n" ); document.write( "x= 16 2/3 qts.
\n" ); document.write( "She should use 16 2/3 qts. of 40% solution.
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "
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