document.write( "Question 554491: using the formula s=2sqrt5x (I am having trouble inserting the radical sign so i used \"sqrt\" i know that is not right everything i used would not work). We will call the speed S (in miles per hour) and x is equal to the length of a skid mark in feet.\r
\n" ); document.write( "\n" ); document.write( "What is the speed of a car that has left a skid mark with a length of 61.25ft? \r
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\n" ); document.write( "\n" ); document.write( "What is the speed of a car that has left a skid mark with a length of 320ft?
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\n" ); document.write( "\n" ); document.write( "How long is the skid mark left by a car that was traveling 70 mph when involved in an accident?
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Algebra.Com's Answer #361354 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
your equation looks like it should be:
\n" ); document.write( "s = 2*sqrt(5x)
\n" ); document.write( "s = the speed of the car in miles per hour.
\n" ); document.write( "x = the length of the skid in feet.
\n" ); document.write( "when x = 61.5 feet, then:\"
\n" ); document.write( "s = 2*sqrt(5*61.5) = 35.071 miles per hour
\n" ); document.write( "when x = 320 feet:
\n" ); document.write( "s = 2*sqrt(5*320) = 80 miles per hour.
\n" ); document.write( "a car traveling at 70 miles per hour would leave a skid mark as described in the following equation:
\n" ); document.write( "70 = 2*sqrt(5x)
\n" ); document.write( "divide this equation by 2 to get:
\n" ); document.write( "35 = sqrt(5x)
\n" ); document.write( "square both sides of this equation to get:
\n" ); document.write( "1225 = 5x
\n" ); document.write( "divide both sides of this equation by 5 to get:
\n" ); document.write( "x = 245 feet.
\n" ); document.write( "a car traveling at 70 miles per hour would leave a skid mark of 245 feet.
\n" ); document.write( "this assumes that it would skid to a stop without hitting anything.
\n" ); document.write( "if it hit something before coming to a stop, then the skid marks would be less than 245 feet.
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