document.write( "Question 554434: If the ratio of the measures of the complementary angle to that of the supplementary angle of the given angle is 1:10, find the ratio of the given angle with its complementary angle? \n" ); document.write( "
Algebra.Com's Answer #361343 by Theo(13342)\"\" \"About 
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cx = complement of x
\n" ); document.write( "sx = supplement of x
\n" ); document.write( "cx/sx = 1/10
\n" ); document.write( "this makes:
\n" ); document.write( "10cx = sx
\n" ); document.write( "cx = 90-x
\n" ); document.write( "sx = 180-x
\n" ); document.write( "this makes:
\n" ); document.write( "10cx = sx become:
\n" ); document.write( "10(90-x) = 180-x
\n" ); document.write( "simplify to get:
\n" ); document.write( "900 - 10x = 180 - x
\n" ); document.write( "add 10x to both sides of this equation and subtract 180 from both sides of this equation to get:
\n" ); document.write( "9x = 720
\n" ); document.write( "divide both sides of this equation by 9 to get:
\n" ); document.write( "x = 80.
\n" ); document.write( "your angle is 80 degrees.
\n" ); document.write( "the complement to this angle is 10 degrees.
\n" ); document.write( "the supplement to this angle is 100 degrees.
\n" ); document.write( "the ratio of the complement to the supplement is 1/10.
\n" ); document.write( "this confirms the angle is good.
\n" ); document.write( "the ratio of the angle to it's complement is equal to
\n" ); document.write( "80/10 = 8/1.
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