document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=554159>Question 554159</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the values of a for which the statement is always true when x is a whole number. explain your reasoning.<BR>\n" );
document.write( "- 2x + a is odd\r<BR>\n" );
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document.write( "- -ax^2 is nonnegative\r<BR>\n" );
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document.write( "- 3x + a is divisible by 3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #361315 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=361315\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -2x + a: Note that -2x is always even. Therefore a must be an odd integer.\r<BR>\n" );
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document.write( "-ax^2: x^2 is nonnegative, so -x^2 is non-positive; setting <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE a \le 0\"> makes the expression nonnegative.\r<BR>\n" );
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document.write( "3x + a: 3x is already divisible by 3, so a must also be divisible by 3. </SPAN>\n" );
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