document.write( "Question 554217: How do you list the possible rational zeros of f in a function using the rational zero theorem?
\n" ); document.write( "f(x)=x^4+2x^2-24
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Algebra.Com's Answer #361289 by KMST(5328)\"\" \"About 
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POSSIBLE RATIONAL ZEROS
\n" ); document.write( "The rational zeros will be rational numbers (fractions) with denominators that are divisors/factors of the leading coefficient, and numerators that are divisors/factors of the independent term.
\n" ); document.write( "For \"f%28x%29=x%5E4%2B2x%5E2-24\" the leading coefficient is the invisible \"1\" in front of \"x%5E4\", and the independent term is \"-24\".
\n" ); document.write( "The only positive divisors/factor of 1 is 1.
\n" ); document.write( "The positive divisors/factors of 24 are:
\n" ); document.write( "1, 2, 3, 4, 6, 8, 12, and 24.
\n" ); document.write( "The possible rational zeros are 1, -1, 2, -2, 3, -3, etc.
\n" ); document.write( "HOW TO FIND THE POSSIBLE RATIONAL ZEROS
\n" ); document.write( "My method to find the factors, was to start with 1, and check integers to see if they would divide 24 evenly. Once I got to a factor that squared was equal or greater than 24, I used another strategy.
\n" ); document.write( "Factors come in pairs that multiply to give you 24:
\n" ); document.write( "1 x 24 = 24,
\n" ); document.write( "2 x 12 = 24
\n" ); document.write( "3 x 8 = 24
\n" ); document.write( "4 x 6 = 24
\n" ); document.write( "Once I got to 6, and saw that \"6%5E2=36%3E24\",
\n" ); document.write( "I found the larger factors from the smaller factors I found before, by dividing as in
\n" ); document.write( "\"24%2F3=8\", and \"24%2F2=12\".
\n" ); document.write( "Another method to find the factors is to work form the prime factorization:
\n" ); document.write( "\"24=2%5E3%2A3\" so the factors/divisors will all be
\n" ); document.write( "\"2%5Ea%2A3%5Eb\", with \"0%3C=a%3C=3\" and \"0%3C=b%3C=1\".
\n" ); document.write( "There are 4 possible values for \"a\" and 2 for \"b\", so I knew there would be 8 factors.
\n" ); document.write( "For a number like 24, calculating them as \"2%5Ea%2A3%5Eb\" would have been a pain, so I used the other method.
\n" ); document.write( "NOTE:
\n" ); document.write( "To find the zeros of \"f%28x%29=x%5E4%2B2x%5E2-24\", I would solve the equation
\n" ); document.write( "\"x%5E4%2B2x%5E2-24=0\" by changing variables to \"y=x%5E2\", so that the equation would transform into
\n" ); document.write( "\"y%5E2%2B2y-24=0\" ---> \"%28y-4%29%28y%2B6%29=0\"
\n" ); document.write( "Back to the original function, I would write it as
\n" ); document.write( "\"f%28x%29=x%5E4%2B2x%5E2-24=%28x%5E2-4%29%28x%5E2%2B6%29=%28x-2%29%28x%2B2%29%28x%5E2%2B6%29\"
\n" ); document.write( "Then I would know that the only real zeros are 2, and -2, which were 2 of the 24 possible rational zeros.
\n" ); document.write( "The factor \"%28x%5E2%2B6%29\" is not zero for any real value of \"x\".
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