document.write( "Question 554180: solve the inequiality x^2+13x+40<5 \n" ); document.write( "

Algebra.Com's Answer #361258 by kkasko(46) $\"\"$ $\"About$

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x^2+13x+40<5
\n" ); document.write( " -5-5
\n" ); document.write( "x^2+13x+40-5<0
\n" ); document.write( "x^2+13x+35<0
\n" ); document.write( " put the equation into the quadratic formula
\n" ); document.write( " $\"x+=+%28-13%29+%2B-+sqrt%28+13%5E2-4%2A1%2A35+%29%29%2F%282%2A1%29+\"$
\n" ); document.write( " $\"x+=+%28-13%29+%2B-+sqrt%2829%29%29%2F%282%29\"$
\n" ); document.write( "The discriminant=29 which means there are two solutions since it is greater than zero.
\n" ); document.write( "x1=-13+sqrt29/(2)
\n" ); document.write( "x1=-3.80741759643275
\n" ); document.write( "x2=-13-sqrt29/(2)
\n" ); document.write( "x2=-9.19258240356725
\n" ); document.write( " -9.19258240356725 < x < -3.80741759643275 \r
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