document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=554037>Question 554037</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given:<BR>\n" );
document.write( "Radius OR is perpendicular to chord AB at C<BR>\n" );
document.write( "AC=2(x-3), BC=x+8\r<BR>\n" );
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document.write( "Find: AC, BC, and AB </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #361176 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=361176\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If the radius, OR, is perpendicular to chord AB, then it bisects AB so that AC = BC.<BR>\n" );
document.write( "2(x-3) = x+8 Solve for x.<BR>\n" );
document.write( "2x-6 = x+8<BR>\n" );
document.write( "x = 14 so...<BR>\n" );
document.write( "AC = 2(x-3) = 2(14-3) = 22.<BR>\n" );
document.write( "BC = x+8 = 14+8 = 22.<BR>\n" );
document.write( "AB = AC + BC = 22+22 = 44. </SPAN>\n" );
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