document.write( "Question 553991: Martin purchased company ABC's stock and invested the balance in his money market account. ABC's stock yielded 18% last year and his money market account yielded 5% last year. If Martin's initial investments amount to $8000 and the annual income is $660, how much money is invested in stock and how much is invested in his money market account? \r
\n" ); document.write( "\n" ); document.write( "Please help me solve this problem. Thank you. \n" ); document.write( "
Algebra.Com's Answer #361156 by Theo(13342)\"\" \"About 
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x was invested in ABC stock.
\n" ); document.write( "y was invested in money market.
\n" ); document.write( ".18x + .05y = 660
\n" ); document.write( "x + y = 8000
\n" ); document.write( "solve these 2 equations simultaneously for your answer.
\n" ); document.write( "from the second equation solve for y to get:
\n" ); document.write( "y = 8000 - x
\n" ); document.write( "substitute in first equation to get:
\n" ); document.write( ".18x + .05(8000-x) = 660
\n" ); document.write( "simplify to get:
\n" ); document.write( ".18x + 400 - .05x = 660
\n" ); document.write( "subtract 400 from both sides of this equation and combine like terms to get:
\n" ); document.write( ".13x = 260
\n" ); document.write( "divide both sides of this equation by .13 to get:
\n" ); document.write( "x = 2000.
\n" ); document.write( "since x + y = 8000, then:
\n" ); document.write( "x = 2000
\n" ); document.write( "y = 6000
\n" ); document.write( "income from x = .18*2000 = 360
\n" ); document.write( "income from y = .05*6000 = 300
\n" ); document.write( "sum of income from both investments = 660.
\n" ); document.write( "everything checks out ok so that's your answer.
\n" ); document.write( "$2000 is invested in stock and $6000 is invested in money market.
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