document.write( "Question 546530: What is the raius of the circle of x^2+4X+y^2+8y=0 \n" ); document.write( "
Algebra.Com's Answer #361139 by lwsshak3(11628)\"\" \"About 
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What is the raius of the circle of x^2+4X+y^2+8y=0
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\n" ); document.write( "Standard form of equation for a circle: (x-h)^2+(y-k)^2=r^2, (h,k)=(x,y) coordinates of center, r=radius
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\n" ); document.write( "x^2+4x+y^2+8y=0
\n" ); document.write( "complete the square
\n" ); document.write( "(x^2+4x+4)+(y^2+8y+16)-4-16=0
\n" ); document.write( "(x+2)^2+(y+4)^2=20
\n" ); document.write( "This is an equation for a circle with center at (-2,-4)
\n" ); document.write( "r^2=20
\n" ); document.write( "radius=√20
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