document.write( "Question 553941: A military tanker left Stapleton Airport at 2:30 pm flying south at 575 mph. An hour and a half later, a bomber left the airport on the same course flying at 800 mph. At what time will the two planes meet for midair refueling? \n" ); document.write( "
Algebra.Com's Answer #361132 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let \"+d+\" = distance the bomber flies until they meet
\n" ); document.write( "Let \"+t+\" = time from 4:00 PM until they meet
\n" ); document.write( "In 1.5 hrs, the tanker gets a head start of
\n" ); document.write( "\"+575%2A1.5+=+862.5+\" mi
\n" ); document.write( "Start a stopwatch when the bomber leaves at 4:00 PM
\n" ); document.write( "-------------------
\n" ); document.write( "Bomber's equation:
\n" ); document.write( "(1) \"+d+=+800t+\"
\n" ); document.write( "Tanker's equation:
\n" ); document.write( "(2) \"+d+-+862.5+=+575t+\"
\n" ); document.write( "( note they are both flying for the same time on stopwatch )
\n" ); document.write( "Substitute (1) into (2)
\n" ); document.write( "(2) \"+800t+-+862.5+=+575t+\"
\n" ); document.write( "(2) \"+225t+=+862.5+\"
\n" ); document.write( "(2) \"+t+=+3.8333+\" ( continuing decimal )
\n" ); document.write( "This is 3 hrs and 50 min on stopwatch
\n" ); document.write( "They meet at 4:00 PM + 3 hrs 50 min = 7:50 PM
\n" ); document.write( "check answer:
\n" ); document.write( "(1) \"+d+=+800%2A3.8333+\"
\n" ); document.write( "(1) \"+d+=+3066.6666+\"
\n" ); document.write( "and
\n" ); document.write( "(2) \"+d+-+862.5+=+575%2A3.8333+\"
\n" ); document.write( "(2) \"+d+=+862.5+%2B+2204.1666+\"
\n" ); document.write( "(2) \"+d+=+3066.6666+\"
\n" ); document.write( "OK\r
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