document.write( "Question 553907: Find the Vertices and the foci of the hyperbola. y^2/5-x^2/11=1. \n" ); document.write( "
Algebra.Com's Answer #361110 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Find the Vertices and the foci of the hyperbola. y^2/5-x^2/11=1 \n" ); document.write( "** \n" ); document.write( "y^2/5-x^2/11=1 \n" ); document.write( "This is an equation of a hyperbola with vertical transverse axis of the standard form: \n" ); document.write( "(y-k)^2/a^2-(x-h)^2/b^2=1, (h,k) being the (x,y) coordinates of the center: \n" ); document.write( "For given equation: \n" ); document.write( "center:(0,0) \n" ); document.write( "a^2=5 \n" ); document.write( "a=√5≈2.24 \n" ); document.write( ".. \n" ); document.write( "b^2=11 \n" ); document.write( "b=√11≈3.32 \n" ); document.write( ".. \n" ); document.write( "c^2=a^2+b^2=5+11=16 \n" ); document.write( "c=√16=4 \n" ); document.write( ".. \n" ); document.write( "vertices: (0,0±a), (0,0±√5)=(0,2.24) and (0,-2.24) \n" ); document.write( "foci: (0,0±c), (0,0±4)=(0,4) and (0,-4) \n" ); document.write( " |