document.write( "Question 553907: Find the Vertices and the foci of the hyperbola. y^2/5-x^2/11=1. \n" ); document.write( "
Algebra.Com's Answer #361110 by lwsshak3(11628)\"\" \"About 
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Find the Vertices and the foci of the hyperbola. y^2/5-x^2/11=1
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\n" ); document.write( "y^2/5-x^2/11=1
\n" ); document.write( "This is an equation of a hyperbola with vertical transverse axis of the standard form:
\n" ); document.write( "(y-k)^2/a^2-(x-h)^2/b^2=1, (h,k) being the (x,y) coordinates of the center:
\n" ); document.write( "For given equation:
\n" ); document.write( "center:(0,0)
\n" ); document.write( "a^2=5
\n" ); document.write( "a=√5≈2.24
\n" ); document.write( "..
\n" ); document.write( "b^2=11
\n" ); document.write( "b=√11≈3.32
\n" ); document.write( "..
\n" ); document.write( "c^2=a^2+b^2=5+11=16
\n" ); document.write( "c=√16=4
\n" ); document.write( "..
\n" ); document.write( "vertices: (0,0±a), (0,0±√5)=(0,2.24) and (0,-2.24)
\n" ); document.write( "foci: (0,0±c), (0,0±4)=(0,4) and (0,-4)
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