document.write( "Question 553738: Give exact and aproximate solutions to y^2-10y+25=49 \n" ); document.write( "
Algebra.Com's Answer #361028 by Earlsdon(6294)\"\" \"About 
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Solve:
\n" ); document.write( "\"y%5E2-10y%2B25+=+49\" Subtract 49 from both sides.
\n" ); document.write( "\"y%5E2-10y-24+=+0\" Factor.
\n" ); document.write( "\"%28y%2B2%29%28y-12%29+=+0\" Apply the zero product rule.
\n" ); document.write( "\"y%2B2+=+0\" or \"y-12+=+0\" so...
\n" ); document.write( "\"y+=+-2\" or \"y+=+12\"
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