document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=553693>Question 553693</A>: <I><SPAN STYLE=\"word-break: break-all;\"> (x+3)^3+(x+5)^3=8 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #361024 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=361024\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I set the equation equal to zero<BR>\n" );
document.write( "(x+3)^3v+ (x+5)^3 - 8 = 0\r<BR>\n" );
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document.write( "and then graphed the function <BR>\n" );
document.write( "y=(x+3)^3 + (x+5)^3 - 8\r<BR>\n" );
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document.write( "Where this graph crosses the x-axis will be solution(s) to the equation.  It happens at x=-3.  I don't know of an easy way to solve it algebraically.  I suppose you could expand the cubes of the binomials, combine like terms, and solve as a polynomial equation.  I can't think of an EASY way to do this.  The graphing calculator is the BEST way, and the solution is x=-3.  It's better than nothing I guess.\r<BR>\n" );
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document.write( "If you or anyone needs to contact me, my Email address is rapaljer@seminolestate.edu.\r<BR>\n" );
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document.write( "Dr. Robert J. Rapalje, Retired<BR>\n" );
document.write( "Seminole State College of Florida<BR>\n" );
document.write( "Altamonte Springs Campus </SPAN>\n" );
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