document.write( "Question 553680: I am buying an \"A\" frame trailer coupler. I am using it a little different than sometimes used. So I know that the angle of the the coupler is 50 degrees. I need to know that if I attach to steel channels to it, and it's going out at 50 degrees, about how far can I go until the width of the ends is about 70 inches.
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\n" ); document.write( "To state it in plain mathematical terms, if I have a triangle where the top angle is 50 degrees, how far will the two sides be so that the bottom of the triangle is 70 inches long?
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Algebra.Com's Answer #361013 by ankor@dixie-net.com(22740)\"\" \"About 
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if I have a triangle where the top angle is 50 degrees, how far will the two sides be so that the bottom of the triangle is 70 inches long?
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\n" ); document.write( "We know the two other angles will be \"%28180-50%29%2F2\" = 65 degrees angles B & C
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\n" ); document.write( "Using the law of sines where A=50 degrees, a = 70 inches, find b or c
\n" ); document.write( "\"sin%28A%29%2Fa\" = \"sin%28B%29%2Fb\"
\n" ); document.write( "\"sin%2850%29%2F70\" = \"sin%2865%29%2Fb\"
\n" ); document.write( "\".766%2F70\" = \".9063%2Fb\"
\n" ); document.write( "Cross multiply
\n" ); document.write( ".766b = 70 * .9063
\n" ); document.write( ".766b = 63.44
\n" ); document.write( "b = \"63.44%2F.766\"
\n" ); document.write( "b = 82.8 ~ 83 inches, the length of the two sides, the ends will be 70 inches apart
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