document.write( "Question 6634: Hi,I really appreciate you trying to help me!! I have this question that I do not really know how to answer, so I hope you can help me, please!!\r
\n" ); document.write( "\n" ); document.write( "\"+log+%28y%2C1%29+\" \"+log+%28y%2Cx%29+\"\r
\n" ); document.write( "\n" ); document.write( "where 1 is less than x and less than y, is the answer positive or negative???\r
\n" ); document.write( "\n" ); document.write( "I think that I am supposed to sub in a number less than 1 in both x and y and see what the sign of the final answer is????? I hope you can help me and thank you!!!!
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Algebra.Com's Answer #3610 by khwang(438)\"\" \"About 
You can put this solution on YOUR website!
Somehow stange since
\n" ); document.write( " \"+log+%28y%2C1%29+\" is always = 0\r
\n" ); document.write( "\n" ); document.write( " Also, use math notation instead of
\n" ); document.write( " \"where 1 is less than x and less than y\"
\n" ); document.write( " means 1 < x < y or (1 < x and 1 < y) ???\r
\n" ); document.write( "\n" ); document.write( " Note if 1 < x < y then \"+log+%28y%2Cx%29+\" < 1\r
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