document.write( "Question 553700: Two minibikes simultaneously left at the same time from certain country club and headed in opposite directions. At the end of an hour and 40 minutes they were 100 km apart. If one of the bikes traveled 5 kph faster that the other, find the speed of each bike? \n" ); document.write( "
Algebra.Com's Answer #360997 by mananth(16946)\"\" \"About 
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mini bike I x mph
\n" ); document.write( "mini bike II x+ 5
\n" ); document.write( "..
\n" ); document.write( "They are going away from each other.
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\n" ); document.write( "So add up their speed.
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\n" ); document.write( "combined speed = x+ 1 x + 5
\n" ); document.write( "( 2 x + 5 )
\n" ); document.write( "Time = 1 2/ 3 hours
\n" ); document.write( "Distance = 100 miles
\n" ); document.write( "Distance = speed * time
\n" ); document.write( "( 2 x 5 )* 12/31/99 = 100
\n" ); document.write( "3.33 x + 8.33 = 100
\n" ); document.write( "3.33 x = 100 + -8.33
\n" ); document.write( "3.33 x = 91.67
\n" ); document.write( "/ 3.33
\n" ); document.write( "x= 27.5 mph mini bike I
\n" ); document.write( "mini bike II 27.5 + 5 = 32.5 mph
\n" ); document.write( "m.ananth@hotmail.ca
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