document.write( "Question 553698: A cargo plane heading east at 240 kph leaves Honolulu airport at 9:30 AM. A passenger plane leaving the same airport at 12:00 noon flies in the same direction. How fast must the passenger plane fly to catch up with the cargo plane by 3:00 PM. How far from the airport will they be? \n" ); document.write( "

Algebra.Com's Answer #360993 by Theo(13342) $\"\"$ $\"About$

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cargo plane leaves at 9:30 am.
\n" ); document.write( "passenger plane leaves at 12:00 noon.
\n" ); document.write( "passenger plan has to catch up with the cargo plane by 3:00 pm.
\n" ); document.write( "in order to do this the passenger plane has to travel the same distance as the cargo plane.
\n" ); document.write( "the cargo plane gets to do it in 5.5 hours because it starts 2.5 hours earlier.
\n" ); document.write( "the passenger plane needs to do it in 3 hours.
\n" ); document.write( "since rate * time = distance, then:
\n" ); document.write( "the cargo plane is traveling at 240 kph for 5.5 hours for a distance of 1320 kilometers.
\n" ); document.write( "the passenger plane is traveling at x kph for 3 hours for a distance of 1320 kilometers.
\n" ); document.write( "this makes x equal to 1320/3 = 440 kph
\n" ); document.write( "the cargo plane travels 5.5 hours at 240 kph for a distance of 1320 km.
\n" ); document.write( "the passenger plane travels 3 hours at 440 kph for a distance of 1320 km. \n" ); document.write( "

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