document.write( "Question 553690: Write an equation for the hyperbola with vertices (4,0) and (-4,0) and asymptote y=1/4x. \n" ); document.write( "
Algebra.Com's Answer #360987 by Theo(13342)![]() ![]() You can put this solution on YOUR website! vertices are (4,0) and (-4,0). \n" ); document.write( "that makes this a horizontally aligned hyperbola. \n" ); document.write( "the center of the hyperbola is midway between the left and right vertex which makes the center equal to (0,0). \n" ); document.write( "the distance from the center to the foci of the hyperbola are called c and are given by the equation c^2 = sqrt(a^2 + b^2). \n" ); document.write( "a is the distance from the vertex to the center which is equal to 4. \n" ); document.write( "the equation for the asymptote of a horizontally aligned hyperbola is y = +/- (b/a) * x \n" ); document.write( "you are given that the equation of the asymptote is y = +/- (1/4)x. \n" ); document.write( "this makes b equal to 1 and a equal to 4. \n" ); document.write( "the formula for a horizontally aligned hyperbola is: \n" ); document.write( "x^2/a^2 - y^2/b^2 = 1 with c = sqrt(a^2 + b^2) \n" ); document.write( "this makes c = sqrt(16+1) = sqrt(17). \n" ); document.write( "this makes the foci at (-sqrt(17),0) and (sqrt(17),0) \n" ); document.write( "so far, the equation of your ellipse is: \n" ); document.write( "x^2/16 - y^2 = 1 \n" ); document.write( "to graph this hyperbola, solve for y to get: \n" ); document.write( "y = +/- sqrt((x^2/16)-1) \n" ); document.write( "to graph the asymptotes, graph the equations of: \n" ); document.write( "y = +/- (1/4)x \n" ); document.write( "the graph will look like this: \n" ); document.write( " \n" ); document.write( "a more far out view is shown below: \n" ); document.write( " \n" ); document.write( "i never remember the formulas and always have to go to the references to get the formula again. \n" ); document.write( "here's a reference i used this time. \n" ); document.write( "http://home.windstream.net/okrebs/page63.html \n" ); document.write( "the foci are not shown on the graph that is mechanically generated. \n" ); document.write( "if you have to show them, then you need to print out the graph and put them there manually. \n" ); document.write( "One of the distinguishing properties of a hyperbola is that the absolute value of the difference of the distance between any point on the hyperbola and the two foci of the hyperbola will be a constant. \n" ); document.write( " \n" ); document.write( " |