document.write( "Question 553682: how do i do.... write an equation of the lin in Plot-slope form that passes through the givin point and has the givin slope,, then convert the point slope equation into Slope- Intercept form \n" ); document.write( "
Algebra.Com's Answer #360986 by KMST(5328)\"\" \"About 
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EXAMPLE
\n" ); document.write( "Let's say you're looking for the equation of a line that passes trough the point (2,1) with slope 1/4. Consider the point given, and a generic point (x,y) on the same line.
\n" ); document.write( " According to the definition of slope, \"%28y-1%29%2F%28x-2%29=1%2F4\"
\n" ); document.write( "Multiplying both sides by \"x-2\" we get
\n" ); document.write( "\"y-1=%281%2F4%29%28x-2%29\" <--This is the point-slope equation found.
\n" ); document.write( "Applying the distributive property to simplify the product, and solving for \"y\"
\n" ); document.write( "\"y-1=%281%2F4%29x-2%281%2F4%29\" ---> \"y-1=%281%2F4%29x-%281%2F2%29\" ---> \"y=%281%2F4%29x%2B1-%281%2F2%29\"
\n" ); document.write( "And that simplifies into the slope intercept-form of the equation
\n" ); document.write( "\"y=%281%2F4%29x%2B1%2F2\"
\n" ); document.write( "IN GENERAL
\n" ); document.write( "The point-slope form of the equation can be derived from the calculation of the slope between any point (x,y) on the line, and the point given.
\n" ); document.write( "Solving that point-slope equation for \"y\" you find the slope-intercept form:
\n" ); document.write( "\"y=slope%2Ax%2Bintercept\"
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